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30n^2-36n+6=0
a = 30; b = -36; c = +6;
Δ = b2-4ac
Δ = -362-4·30·6
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-24}{2*30}=\frac{12}{60} =1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+24}{2*30}=\frac{60}{60} =1 $
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